{"id":18013,"date":"2024-04-17T02:14:47","date_gmt":"2024-04-17T02:14:47","guid":{"rendered":"https:\/\/soicaulode866.com\/?p=18013"},"modified":"2024-04-17T02:14:47","modified_gmt":"2024-04-17T02:14:47","slug":"kinh-nghiem-danh-de-trung-100-theo-cong-thuc","status":"publish","type":"post","link":"https:\/\/soicaulode866.com\/kinh-nghiem-danh-de-trung-100-theo-cong-thuc\/","title":{"rendered":"kinh nghi\u1ec7m \u0111\u00e1nh \u0111\u1ec1 tr\u00fang 100% theo c\u00f4ng th\u1ee9c"},"content":{"rendered":"
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C\u00e1ch \u0111\u00e1nh \u0111\u1ec1 tr\u00fang 100% – C\u00e1ch \u0111\u00e1nh \u0111\u1ec1 mi\u1ec1n B\u1eafc, l\u00f4 \u0111\u1ec1 \u0103n ch\u1eafc ch\u00ednh x\u00e1c nh\u1ea5t hi\u1ec7n nay \u0111\u01b0\u1ee3c s\u01b0u t\u1ea7m t\u1eeb nhi\u1ec1u ngu\u1ed3n tin c\u1eady v\u00e0 \u0111\u01b0\u1ee3c c\u00e1c chuy\u00eang gia soi c\u1ea9u \u0111\u00e1nh gi\u00e1 cao nh\u1ea5t d\u01b0\u1edbi \u0111\u00e2y, b\u1ea1n h\u00e3y \u0111\u1ecdc k\u1ef9 kh\u00f4ng n\u00ean b\u1ecf qua nh\u00e9.<\/p>\n\n\n\n
C\u00e1ch \u0111\u00e1nh \u0111\u1ec1 mi\u1ec1n b\u1eafc \u0111\u01b0\u1ee3c Soi c\u1ea7u l\u00f4 \u0111\u1ec1 tr\u01b0\u1edbc \u0111\u00f3 cung c\u1ea5p cho \u0111\u1ed9c gi\u1ea3 r\u1ea5t nhi\u1ec1u, trong b\u00e0i n\u00e0y ch\u00fang t\u00f4i s\u1ebd t\u1ed5ng h\u1ee3p nh\u1eefng c\u00e1ch \u0111\u00e1nh l\u00f4 \u0111\u1ec1 b\u1ea1ch th\u1ee7 c\u00f3 t\u1ef7 l\u1ec7 \u0103n cao nh\u1ea5t, c\u1ee5 th\u1ec3 chi ti\u1ebft s\u1ebd \u0111\u01b0\u1ee3c vi\u1ebft chi ti\u1ebft d\u01b0\u1edbi \u0111\u00e2y:<\/p>\n\n\n\n
– Ph\u01b0\u01a1ng ph\u00e1p n\u00e0y s\u1eed d\u1ee5ng k\u1ebft qu\u1ea3 s\u1ed1 \u0111\u1ec1 2 ng\u00e0y tr\u01b0\u1edbc \u0111\u1ec3 \u0111\u00e1nh cho ng\u00e0y h\u00f4m nay b\u1eb1ng c\u00e1ch c\u1ed9ng t\u1ed5ng s\u1ed1 h\u00e0ng \u0111\u01a1n v\u1ecb v\u1edbi h\u00e0ng ch\u1ee5c c\u00f9ng m\u1ed9t s\u1ed1 b\u1ea5t k\u1ef3 \u0111\u1ec3 ra t\u1ed5ng ch\u1eb5n 10 v\u00e0 ch\u1eb5n 20.<\/p>\n\n\n\n
C\u1ee5 th\u1ec3: G\u1ecdi k\u1ebft qu\u1ea3 \u0111\u1ec3 c\u1ee7a 2 ng\u00e0y tr\u01b0\u1edbc \u0111\u00f3 l\u1ea7n l\u01b0\u1ee3t l\u00e0 AB v\u00e0 CD ta c\u00f3:<\/p>\n\n\n\n
A + B + X = 10 (ho\u1eb7c 20)<\/p>\n\n\n\n
C + D + Y = 20 (ho\u1eb7c 20)<\/p>\n\n\n\n
Nh\u01b0 v\u1eady \u0111\u00e1nh l\u00f4 XY cho ng\u00e0y th\u1ee9 3.<\/p>\n\n\n\n
+ C\u1ea7u n\u00e0y v\u1ec1 th\u00ec th\u01b0\u1eddng v\u1ec1 t\u1eeb 3 \u0111\u1ebfn 4 ng\u00e0y.<\/p>\n\n\n\n
+ N\u1ebfu ng\u00e0y th\u1ee9 3 kh\u00f4ng v\u1ec1 th\u00ec ngh\u1ec9 ng\u00e0y th\u1ee9 4, ng\u00e0y th\u1ee9 5 l\u00f4 v\u1ec1 th\u00ec v\u1eabn ngh\u1ec9 ng\u00e0y th\u1ee9 6, \u0111\u1ebfn ng\u00e0y th\u1ee9 7 t\u00ednh t\u1eeb th\u1eddi \u0111i\u1ec3m t\u00ednh c\u1ea7u m\u00e0 c\u1ea7u ra th\u00ec m\u1edbi b\u1eaft \u0111\u1ea7u theo.<\/p>\n\n\n\n
+ N\u1ebfu quan s\u00e1t th\u1ea5y 5 ng\u00e0y c\u1ea7u kh\u00f4ng ra th\u00ec \u0111\u1ebfn ng\u00e0y th\u1ee9 6 m\u1edbi \u0111\u00e1nh c\u1ea7u n\u00e0y, n\u1ebfu ng\u00e0y th\u1ee9 6 v\u1eabn to\u1ea1ch th\u00ec ngh\u1ec9 ti\u1ebfp ng\u00e0y th\u1ee9 7, sau \u0111\u00f3 3 ng\u00e0y ti\u1ebfp \u0111\u00e1nh c\u1ea7u n\u00e0y \u0103n ch\u1eafc.<\/p>\n\n\n\n
+ Tr\u01b0\u1eddng h\u1ee3p \u0111\u00e1nh XY m\u00e0 v\u1ec1 YX th\u00ec ngh\u1ec9 3 \u0111\u1ebfn 4 ng\u00e0y r\u1ed3i m\u1edbi theo l\u1ea1i c\u1ea7u.<\/p>\n\n\n\n
VD: Ng\u00e0y 17\/6\/2024 \u0111\u1ec1 v\u1ec1 44, ng\u00e0y 18 \u0111\u1ec1 v\u1ec1 76, nh\u01b0 v\u1eady theo c\u00f4ng th\u1ee9c ta c\u00f3:<\/p>\n\n\n\n
4 + 4 + 2 = 10<\/p>\n\n\n\n
7 + 6 + 7 =20<\/p>\n\n\n\n
\u0110\u00e1nh l\u00f4 27 \u0111\u00e1nh cho c\u00e1c ng\u00e0y k\u1ebf.<\/p>\n\n\n\n
Ng\u00e0y 19 l\u00f4 27 kh\u00f4ng v\u1ec1, ngh\u1ec9 \u0111\u00e1nh.<\/p>\n\n\n\n
Ng\u00e0y 20 l\u00f4 27 kh\u00f4ng v\u1ec1.<\/p>\n\n\n\n
Ng\u00e0y 21, 22, 23 \u0111\u1ec1u kh\u00f4ng v\u1ec1, nh\u01b0 v\u1eady XY r\u01a1i v\u00e0o tr\u01b0\u1eddng h\u1ee3p th\u1ee9 3 tr\u00ean, c\u1edd th\u1eddi c\u01a1.<\/p>\n\n\n\n
Ng\u00e0y 24\/6 (c\u00e1ch 6 ng\u00e0y) l\u00f4 27 v\u1ec1, \u0111\u00e1nh \u0111\u1ec1 c\u1ea7u n\u00e0y cho 3 ng\u00e0y k\u1ebf.<\/p>\n\n\n\n
\u0110\u1ebfn 26\/6 \u0111\u1ec1 v\u1ec1 27.<\/p>\n\n\n\n
Ti\u1ebfp v\u00ed d\u1ee5 ng\u00e0y 3\/7\/2024 \u0111\u1ec1 v\u1ec1 86, ng\u00e0y 4\/7 \u0111\u1ec1 v\u1ec1 48.<\/p>\n\n\n\n
Nh\u01b0 v\u1eady theo c\u00f4ng th\u1ee9c ta c\u00f3 XY = 68<\/p>\n\n\n\n
Ng\u00e0y 5\/7 l\u00f4 v\u1ec1 68.<\/p>\n\n\n\n
Ng\u00e0y 6\/7 l\u00f4 v\u1ec1 68.<\/p>\n\n\n\n
Ng\u00e0y 7\/7 l\u00f4 v\u1ec1 68.<\/p>\n\n\n\n
Ng\u00e0y 8\/8 l\u00f4 v\u1ec1 68.<\/p>\n\n\n\n
Soi c\u1ea7u XSMB gi\u1ea3i 3 th\u01b0\u1eddng c\u00f3 c\u1ea7u \u0103n b\u00f3ng cho \u0111\u1ec1 th\u1eb3ng ng\u00e0y h\u00f4m sau, ta c\u00f3 6 l\u1ef1a ch\u1ecdn \u0111\u1ec3 \u0111\u00e1nh v\u1edbi c\u1ea7u b\u00f3ng c\u1ee5 th\u1ec3:<\/p>\n\n\n\n
Ta c\u00f3<\/p>\n\n\n\n
– B\u00f3ng D\u01b0\u01a1ng c\u1ee7a c\u00e1c con s\u1ed1: 0-5; 1-6; 2-7; 3-8; 4-9 (v\u00e0 ng\u01b0\u1ee3c l\u1ea1i)<\/p>\n\n\n\n
– B\u00f3ng \u00c2m c\u1ee7a c\u00e1c con s\u1ed1: 0-7; 1-4; 2-9; 3-6; 5-8 (v\u00e0 ng\u01b0\u1ee3c l\u1ea1i)<\/p>\n\n\n\n